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Topic: Not your usual "disclosure" scenario... (Read 5846 times) 

Zon
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Re: Not your usual "disclosure" scenario...
« Reply #15 on: Oct 9^{th}, 2015, 1:02pm » 

Yes, yada. We are much more powerful than the Cicada 3301. We understand Pi. Here is some formulas: sec<tan<x yπ 2345tan<√14>> y cos<x x^3πy cos√3456>>> y•cos<y x^3π sec<x √1568>> y x^3x•√3456<sec<y 18x^2>> y•csc<x sec<π 568<cos<√22>>>> x•<y sec<π9 tan<π3 x^2√568>>> x^2x^2 π9 π8 sec<√568<cos<9y>>> x^2y cos< π5sec<√tan<x^2<y>>> y•cos<8x^2√23√6x^38tan<y•√x•x>>> x^28cos<y•<x•x^345√23x^2<y•√x^2x>>> x^2tan<xπ<58√sinh<√9x^3sec<12x^2y>>> y•tanh<x^3568<12x^3√23<x>>> 8x^2y•arctan<√234<√x•x^3y•cos<7>>> x^2tan<8x^2cos<x^2<24√56<x•sin<y>>>> cos<x^32345x^2<y•√1568<9x^2x>>> [RL] cos<x^33456x^2<y•√1568<9x^2x>>> [LR] 9x^3cos<x•<√y•x^2568<y8>>> x^2y•sin<2345x^3 23 24√y•x> y•csc<x^2arcsin<√56<8x^2y>>> x^2arctan<3 √9 tan<e^π<y•x^2x> π8 x^2 y•x•<x^2√csc<8<156<x>>>> 9 yπx^31568sec<x•<y•cos<56>>> x^2cos< sec<πy•<x•x^3cos<√568>>>> tan<πy cos<x•<x^35tanh<πx>>>> sin<yπ cosh<x•x^35tanh<πx>>> sin<πy cos<x•<x^25tanh<πy>>>> cos<πy•x cos<x•<x^33tanh<πx>>>> 568<πy•cos<y•<sin<√8x^225<x2.5>>>>> 568 ln<x^29<csc<y √12<x^2y>>>> 360 ln<<x^7<csc<y √7<x^2y 7>>>>> y•csch<xπ x^2 56<3cos<√23>>> 56cos<y 8x^3 x12√8> xπcos<yπ x^3y x^3x^2√56> π cos<y x^2 x^38x^3sin<234>> π cos<y x^2 x^38x^3sin<156>> π cos<y x^2 x^38x^3sin<345>> x5 cos<3 568 sec<x^3y•<8>>> sech<8 x^3y•<x^2π 34√56>> x cos< x^2y•<x^38√56<y•y>>> y•arcsin< y•x^2x•√x^3<56y•y>>> xπcos<x^2 x^3 x^2y•<8x^2√568> tanh<xπ sec<x^3x y•x^3√568>> x•arcsec<y•<x^3234x•cos< √32>>>


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Zon
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Re: Not your usual "disclosure" scenario...
« Reply #16 on: Oct 9^{th}, 2015, 1:05pm » 

You see, the Q5 device I am using does not parse correctly for you're string systems. Need understanding where a simple post of drawings can be uploaded without extra tagging from this internet system...


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DrDil
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Re: Not your usual "disclosure" scenario
« Reply #17 on: Oct 9^{th}, 2015, 1:19pm » 

on Oct 9^{th}, 2015, 1:02pm, Zon wrote:Yes, yada. We are much more powerful than the Cicada 3301. We understand Pi. Here is some formulas: sec<tan<x yπ 2345tan<√14>> y cos<x x^3πy cos√3456>>> y•cos<y x^3π sec<x √1568>>
<snip> 

Welcome Zon,
Formulas for what?
They don't resolve/make any sense do they?
Cheers.


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Zon
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Re: Not your usual "disclosure" scenario...
« Reply #18 on: Oct 9^{th}, 2015, 1:54pm » 

I found pastebin.. of some logs of uploading at this link > http://pastebin.com/5HN2k1nn but where drawings to upload without all the tagging... The Q5 device I am using does not allow remote url parsing with both channels.


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ZETAR
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GREAT SPIRITS ALWAYS ENCOUNTER THE MOST VIOLENT OPPOSITION FROM MEDIOCRE MINDS E=MC2
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Re: Not your usual "disclosure" scenario...
« Reply #19 on: Oct 9^{th}, 2015, 2:13pm » 

ZON,
SINCE OUR MATH MUST BE ANTIQUATED...IT IS IMPERITIVE THAT YOU CLARIFY SOME ASPECTS OF YOUR EQUATION...WHICH IN FACT LACKS >>> = <<< ~ OR FORMULA IF YOU WILL...
In mathematics, a formula is an entity constructed using the symbols and formation rules of a given logical language.[2] For example, determining the volume of a sphere requires a significant amount of integral calculus or its geometrical analogue, the method of exhaustion;[3] but, having done this once in terms of some parameter (the radius for example), mathematicians have produced a formula to describe the volume: This particular formula is:
V = 4/3π r3
WE'RE ON THE PAGE WITH YOU REFERENCING PI = 3.14159265359
HOWEVER...
FURTHER...
DRDIL MAKES AN ASTUTE OBSERVATION
"Formulas for what?
They don't resolve/make any sense do they?"
MATH SHOULD BE UNIVERSAL IN YOUR TIME ~ OUR TIME...WE ACTUALLY NEED YOU TO PROVIDE SPECIFIC GIVENS ~
IT MIGHT AID IN CASEBOOK APPROACHING UR INTENT...
UR ATTENTION TO THE ABOVE REFERENCED WOULD BE MOST APPRECIATED.
SHALOM...Z
EDIT TO ADD:
WE NEED YOU TO CONNECT THE DOTS FOR THE >>> rules of a {YOUR} given logical language <<<

« Last Edit: Oct 9^{th}, 2015, 2:42pm by ZETAR » 
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GREAT SPIRITS ALWAYS ENCOUNTER THE MOST VIOLENT OPPOSITION FROM MEDIOCRE MINDS E=MC2



Zon
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Re: Not your usual "disclosure" scenario...
« Reply #20 on: Oct 9^{th}, 2015, 2:45pm » 

Shabbat shalom. The intent is to disclose these maths with me to where I am going back, 3015. I understood what you included, but the include is of Arabic orgin mathematics. Of the purpose of the to disclose has no nothing center, as with the Menorah, the symbol of all true math from One. Adam did not have concept of nothing or zero before he believed naked.


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Zon
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Re: Not your usual "disclosure" scenario...
« Reply #21 on: Oct 9^{th}, 2015, 2:50pm » 

I hope you will understand importance of this. The nations are soon to converge on a resolution to accept human tagging so as to eliminate economic worries, but becomes wrath and famine.


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BARSOOM
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Re: Not your usual "disclosure" scenario
« Reply #23 on: Oct 9^{th}, 2015, 6:31pm » 

on Oct 9^{th}, 2015, 3:39pm, Zon wrote:
While data mining for your Q5 device I found nothing much but a socalled "Q486" device, complete with vectordrawn plans and a CGI model.
I thought it was fake at first.
Could this be the schematics of your maths device?
Why not just write it out  the functions, etc., in a simp language like PERL for we past time ancients?
Perhaps?
+BARSOOM ^{(told you I had water!)}


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ZETAR
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Re: Not your usual "disclosure" scenario...
« Reply #25 on: Oct 9^{th}, 2015, 6:47pm » 

BARSOOM,
TO WIT:
"Why not just write it out  the functions, etc., in a simp language like PERL for we past time ancients?"
>>> I LIKEY! <<<
SHALOM...Z


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GREAT SPIRITS ALWAYS ENCOUNTER THE MOST VIOLENT OPPOSITION FROM MEDIOCRE MINDS E=MC2



INT21
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Re: Not your usual "disclosure" scenario...
« Reply #26 on: Oct 9^{th}, 2015, 6:49pm » 

If a=106.2602
Thus sin(a)= 0.96
Please explain how
Sin(a)=y1/25 = 0.96
HAL INT21


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Zon
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Re: Not your usual "disclosure" scenario...
« Reply #27 on: Oct 9^{th}, 2015, 7:12pm » 

The Q5 I am using for login is logged on to protected transfer layers and parsing is regulated by the two channels. The answer to the question is similar to pstore instruction with epm instruction for of similarity :: y昪os<8x^2√23√6x^38tan<y√x晉>, whereof as illustrated further :: indexSync(ctrlA,ctrlB,ctrlN(span(num*epm)


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Zon
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Re: Not your usual "disclosure" scenario...
« Reply #28 on: Oct 9^{th}, 2015, 7:17pm » 

I left it open param for of who can understand maybe... We have no relationship with Freemasonry or the Cicada 3301. Those orgs rely on men.


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